Batboard

hi all
I have just acquired a Motorola rln1014a battery eliminator for the mts2000/ht1000 ect and have a few questions if anybody can help
does the dc input have to be 7.5v or can 12/13v be used.
Also there is bullet lead for mobile radios, is this to power the mobile radio when the battery eliminator is powered from a dc supply if so
again what voltage is used. Any help would be great as I would like to set this up for powering my handhelds and mobiles while programming
If any one has a manual of this it would be great.Thanks

I can NOT say IF the 'battery eliminator' has a voltage regulator in it. I doubt they had a regulator, maybe a blocking/reverse polarity diode. These were used on the test bench.
The dual banana plug was for DC input. You could measure the voltage on the 'battery contacts'.

http://www.ebay.com/itm/NEW-NOS-RARE-MO ... 1726396980

Hi will
thanks for the reply.I do know the handhelds are 7.5v dc input but what is confusing me is the mobile radio lead on the eliminator I would guess this is to power mobile radios maybe I am wrong but would imagine they need 13.8v or so.There does not seem to a lot on the about these as they seem to be rare.
If anyone has one they might let me know.

According to the paperwork that comes with them it's designed to run off of a 7.5VDC supply of at least 5A current capacity.
It has an SCR crowbar overvoltage protection circuit and reverse polarity protection.

The other connector that looks like a mobile power plug is a power take-off to power an RLN-4018 test fixture, it warns you not to input power to that connector, as damage to the radio may result.

Thank you jack,
That's just the info I needed your a star.